Question

There are 75 boys and 45 girls in class X of a school. Principal of the school decided to have separate sections for boys and girls, each section containing the same number of boys or girls. Find the minimum number of sections required to accommodate the students and the number of students in each section​

Answer 1

Question: In a School, 437 boys and 342 girls have been divided into classes so that each class has the same number of students and number of boys and girls mixed. what is the least number of classes needed?

Solution: Each class should have the maximum number of students.

So, HCF of 437, 342 = 19

HCF is also the factor of difference of the number.

Therefore, Number of classes =

$\frac{437}{19} + \frac{342}{19} = 23 + 18 = 41 \: classes$