There are 8 different lines, 7 different circles and 6 different equilateral triangles, then maximum number of points on ntersections of
ADD
Answers
Given : 8 different lines, 7 different circles and 6 different equilateral triangles,
To Find : maximum number of points of intersections
Solution:
8 Lines
7 circles
6 Equilateral Triangles
8 Lines can intersect with each other in ⁸C₂ = 28
1 Line can intersect a circle at 2 points hence 8 x 7 x 2 = 112
A line can intersect an equilateral triangle at 2 points = 8 x 6 x 2 = 96
A Circle can intersect another circle at 2 point = 2 x ⁷C₂ = 42
A triangle can intersect another triangle at 6 points = 6 x ⁶C₂ = 90
A triangle and circle can intersect at 6 points => 6 x 6 x 7 = 252
Maximum point of intersections = 28 + 112 + 96 + 42 + 90 + 252
= 620
maximum number of points on intersections = 620
Learn More:
If points S, O, and N are collinear, how many lines do they determine ...
https://brainly.in/question/18187924
the points p, q, r, s are collinear if points s, t,a, b are collinear then ...
https://brainly.in/question/11405922