there are 8 rooms on the first floor of a hotel with 4 rooms on each side of the corridor, symmetrically situated . 4 guests have to be accommodated in 4 of the 8 rooms ( one in each room) such that no two guests are in adjacent rooms or in opposite rooms . In how many ways can the guests be accommodated??
Answers
Answered by
6
in 2 ways
in the rooms
(i) A,D,E,H
(ii) B,C,F,G
you took part in the Olympiad right
this question was in that.
Hope that this will help you
if you like my way of answering please mark as brainliest
if you want further help you can ask me anytime
Thank you
-Sneha
in the rooms
(i) A,D,E,H
(ii) B,C,F,G
you took part in the Olympiad right
this question was in that.
Hope that this will help you
if you like my way of answering please mark as brainliest
if you want further help you can ask me anytime
Thank you
-Sneha
Attachments:
deyanisha:
sorry to say your answer is wrong
how??
what is the correct answer then
n my answer is correct
correct answer is 48
answers are given in internet
how?
explain
there is a formula or method. I don't know that . But I have got the answer 48 in internet
Answered by
7
Answer:
48.
Step-by-step explanation:
Soln. (48)
The rooms can be selected in only two possible ways as follows :
In each case guests can be accommodated in 4! ways.
becoz the guests are different so they can be arranged in 4 factorial ways
required number of ways 2 4 = 48
Similar questions