Question

There are a number of chocolates in a bag. if they were to be equally divided among 14 children, there are 10 chocolates left. if they were to be equally divided among 15 children, there are 8 chocolates left. obviously, this can be satisfied if any multiple of 210 chocolates are added to the bag. what is the remainder when the minimum feasible number of chocolates in the bag is divided by 9?

Answer 1

Let there will be X chocolates is given to each children.

from first condition total number of chocolates=14*X+10

from second condition total number of chocolates=15*X+8

14*X+10=15*X+8

X=2

so total number of chocolates=14*2+10=38

when multiple of 210 chocolates added with total number of

chocolates then number of chocolates=38+210=248

when this is divided by 9 then remainder=5 ..

Please mark it as brainiest answer ..........

Answer 2

Answer:

5

Step-by-step explanation:

Let number of chocolates received by each child when there were 14 children = k

Let number of chocolates received by each child when there were 15 children = m

Hence we have 14k + 10 = 15m + 8

Hence we have the value of k = (15m – 2)/14

Putting the value of m = 2

We have k = 2

Hence we have 14k + 10 chocolates

i.e.  14 × 2 + 10

= 28 + 10

= 38 chocolates.

When multiple of 210 chocolates added with the total number of chocolates

⇒ then the number of chocolates = 38+210 = 248

We need to find what is the remainder when 248 is divided by 9

Hence we get 5 as remainder when 248 is divided by 9