There are boxes A B and C .the probability of getting white ball from box A is 1/2from boxB is 2/3 and from box C is 3/4.A box is chosen at random and three balls are drawn from it without replacement and it was found that two of them were white what is the probability that box B is chosen
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Answer:
option is
B
39
14
In a box,
B
1
=1R,2W
B
2
=2R,3W
and B
3
=3R,4W
Also, given that,
P(B
1
)=
2
1
,P(B
2
)=
3
1
and P(B
3
)=
6
1
∴P(
R
B
2
)=
P(B
1
)P(
B
1
R
)+P(B
2
)P(
B
2
R
)+P(B
3
)P(
B
3
R
)
P(B
2
)P(
B
2
R
)
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