Question

There are certain no. of students in class X A and class X B if 10 students are sent from X A to X B the no. of students in both the classes is the same if 20 students are sent from XB to X A the no. of students in X A is double the no. of students in X B find the no. of students in both classes?​

Answer 1

Answer:

is given that there are 32 students in section A and 36 students in section B. 

To determine the minimum number of books required to distribute equally among students of section A and section B, we need to find the LCM of 32 and 36.

To find the LCM, we find the prime factors of 32 and 36 as follows:

Prime factors of 32 are 2. Prime factorization of 32 in exponential form is:

32=25

Prime factors of 36 are 2,3. Prime factorization of 36 in exponential form is:

36=22×32

Now multiplying the highest exponent prime factors to calculate the LCM of 32 and 36, we have:

LCM(32,36)=25×32=288

Hence, the minimum number of books required to distribute equally among students of section A and section B

Answer 2

Answer:

XA students = 100

XB students = 80

Step-by-step explanation:

Let no of students in XA be a.

Let no of students in XB be b.

b + 10 = a-10  -------> 1

2(b - 20) = a + 20 ---------> 2

From 1,

a = b + 20 -----------> 3

Put 3 in 2,

2(b - 20) = b + 20 + 20

2b - 40 = b + 40

b = 80.

Since b = 80,

a = 100

So XA students are 100 and XB students are 80.

HOPE IT HELPS!!!