There are crows and groundhogs in a field. All of them together have 15 heads and 40 legs. How many of each animal are in the field?
Answers
Answered by
1
Answer:
Let
x=# of chickens
y=# of goats
Each chicken and goat has 1 head.
Each chicken has 2 legs. Each goat has 4 legs.
This results in the following system of equations:
x+y=43
2x+4y=108
Solve for x in first equation:
x=43-y
Substitute x in other equation to get:
2x+4y=108
2(43-y)+4y=108
86-2y+4y=108
2y=22
y=11
x+y=43
x+11=43
x=32
Answered by
1
Answer:
groundhogs must be inside of soil so their legs will be not visible . therefore 40 legs means 10 cows .. and that means 5 groundhogs
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