Math, asked by carameI, 9 months ago

There are crows and groundhogs in a field. All of them together have 15 heads and 40 legs. How many of each animal are in the field?

Answers

Answered by Anonymous
1

Answer:

Let

x=# of chickens

y=# of goats

Each chicken and goat has 1 head.

Each chicken has 2 legs. Each goat has 4 legs.

This results in the following system of equations:

x+y=43

2x+4y=108

Solve for x in first equation:

x=43-y

Substitute x in other equation to get:

2x+4y=108

2(43-y)+4y=108

86-2y+4y=108

2y=22

y=11

x+y=43

x+11=43

x=32

Answered by harshvardhangau
1

Answer:

groundhogs must be inside of soil so their legs will be not visible . therefore 40 legs means 10 cows .. and that means 5 groundhogs

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