Question

There are five electric appliances, viz. electric heater and electric lamp, an electric fan, computer and an exhaust fan are connected in parallel in a household. The resistance electric appliances are 40Ω, 5 Ω, 8Ω, 20Ω and 10Ω respectively. If an electric current of 240 V is flowing through the circuit then find a) Total resistance through the circuit b) Total electric current (I) through the circuit and c) The current through each of the resistor

class 10th science ​

Answer 1

Solution;

a.

given,

R1=40ohm,R2=5ohm,R3=8ohm,R4=20ohmand R5=10ohm.

Total resistance

1/R=1/R1+1/R2+1/R3+1/R4+1/R5

1/R=1/40+1/5+1/8+1/20+1/10

1/R=(1+8+5+2+4)/40

1/R=20/40

1/R=1/2

R=2ohm

So, Total resistance is 2ohm.

b.

we know that,

V=IR

240=I*2

I=120A

So, electric current is 120A.

c.

current through each resistor as follows;

we know that,

V=IR

I=V/R

I1=240/40

I1=6A

I2=240/5

I2=48A

I3=240/8

I3=30A

I4=240/20

I4=12A

I5=240/10

I5=24A

Answer 2

Solution;

a.

given,

R1=40ohm,R2=5ohm,R3=8ohm,R4=20ohmand R5=10ohm.

Total resistance

1/R=1/R1+1/R2+1/R3+1/R4+1/R5

1/R=1/40+1/5+1/8+1/20+1/10

1/R=(1+8+5+2+4)/40

1/R=20/40

1/R=1/2

R=2ohm

So, Total resistance is 2ohm.

b.

we know that,

V=IR

240=I*2

I=120A

So, electric current is 120A.

c.

current through each resistor as follows;

we know that,

V=IR

I=V/R

I1=240/40

I1=6A

I2=240/5

I2=48A

I3=240/8

I3=30A

I4=240/20

I4=12A

I5=240/10

I5=24A