there are
five terms in an AP
the sum of these terms as 55. & the
fougth terims is five more than the
Sum of the first two teams . Find
the terms of API
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n=5, S5=55,
a4=a+a2+5
=>2a+2d=a+a+d+5
=>2a+2d=2a+d+5
=>2a-2a=d+5-2d
=>-d+5=0
=>d=5,
Sn=n/2(2a+(n-1)d)
=>55=5/2(2a+4*5)
=>55=5/2(2a+20)
=>2a+20=55*2/5
=>2a=22-20
=>a= 2/2= 1
=>a= 1
So the AP is 1,6,11,16,21
so this is your answer I hope it helps
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