Question

There are four forces acting on a
particle P, which then continues
to remain at rest. Evaluate the
forces F, and F2.

Answer it only if uh know the correct explanation.​

Answer 1

Answer:

F₁ = (1/√2) N and F₂ = (3/√2) N

Explanation:

Applying equilibrium conditions. :

Horizantal Forces :

F₁ + 1 sin 45° - 2 sin 45° = 0

⇒ F₁ = 2 sin 45° - 1 sin 45°

⇒ F₁ = sin 45°

⇒ F₁ = (1/√2)    ------ (1)

Now,

Vertical Forces :

2 cos 45°  + 1 cos 45° - F₂ = 0

⇒ 3 cos 45° - F₂ = 0

⇒ 3 cos 45° = F₂

⇒ 3(1/√2) = F₂

⇒ 3/√2 = F₂

Therefore,

F₁ = (1/√2) N and F₂ = (3/√2) N

Hope it helps!