there are four unknown numbers, the mean of first two numbers is 4 and mean of first three numbers is 9 the mean of all four numbers is 15 if one of the number is 2 find other numvers
Answers
Answered by
15
Let numbers be x1,x2,x3 and x4
We have x1 = 2
We are given,
x1 + x2 = 8
so, x2 = 8-2 = 6
Then, x1 + x2 + x3 = 27
so, x3 = 27 -8
x3 = 19
We also have, x1+x2 + x3 + x4 = 60
so, 27 + x4 = 60
so, x4 = 33
Hence, Numbers are 2,6,19 and 33
We have x1 = 2
We are given,
x1 + x2 = 8
so, x2 = 8-2 = 6
Then, x1 + x2 + x3 = 27
so, x3 = 27 -8
x3 = 19
We also have, x1+x2 + x3 + x4 = 60
so, 27 + x4 = 60
so, x4 = 33
Hence, Numbers are 2,6,19 and 33
Answered by
5
Answer:
The four numbers are 2, 6, 19, 33
Step-by-step explanation:
Let the number be
According to the question
The mean of first two numbers = 4
and one of the number is 2.
So, suppose
We know that
∵
And the mean of first three numbers = 9
So,
Now, the mean of all four numbers = 15
Hence the four numbers are 2, 6, 19, 33.
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