C=(-a, b) and r=a+b. find equation of circle
Answers
Answered by
1
Formula-
When c(h,k)&r=a
(x-h) ^2+(y-k)^2=a^2
Thus
(x+a)^2+(y-b)^2=(a+b)^2
X^2+y^2+2ax-2by-2ab=0
When c(h,k)&r=a
(x-h) ^2+(y-k)^2=a^2
Thus
(x+a)^2+(y-b)^2=(a+b)^2
X^2+y^2+2ax-2by-2ab=0
Answered by
1
Formula-
When c(h,k)&r=a
(x-h) ^2+(y-k)^2=a^2
Thus
(x+a)^2+(y-b)^2=(a+b)^2
X^2+y^2+2ax-2by-2ab=0
When c(h,k)&r=a
(x-h) ^2+(y-k)^2=a^2
Thus
(x+a)^2+(y-b)^2=(a+b)^2
X^2+y^2+2ax-2by-2ab=0
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