there are n A.Ms.between 3 and 17 the ratio of last mean to the first mean is 3:1 .find value of n .
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let the first am be x. then the last am will be 3x.
the last am is divisible by three. so use hit n trial method. take the last am as 15. the difference is 2. so the first am will be 3+2=5.
this satisfies x and 3x. n will be 6
the last am is divisible by three. so use hit n trial method. take the last am as 15. the difference is 2. so the first am will be 3+2=5.
this satisfies x and 3x. n will be 6
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