There are n infinite metal plates arranged parallel to each other as shown. q1, q2 , ...., qn are respective charges on these plates. Chargeq on the left surface of left most plate is ?1) (q1 + q2 +...+qn)/22) (q1 + q2 +---+qn)/n3) 04) none
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2
Answer:
Correct option is
D
(Q
1
−Q
2
)/(2C)
The potential difference between the two identical metal plates is given as
C=
d
ε
0
A
Let the surface charge density is given as
σ
1
=σ
21
=
A
Q
The net electric field is
E
net
=
2ε
0
σ
1
−σ
2
We know the potential difference is given as
V=E.d
By substituting the above values we get
V=
2C
Q
1
−Q
2
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