Question

there are n perfect square natural numbers between 200 and 1000. write the value of n.​

Answer 1

The first perfect square after 200 is 225, the last perfect square before 1000 is 961

Squar root of 225 =√(15*15)=15

And square root of 961 = √(31*31)= 31

So the answer is 31–15+1 = 17

(* +1 is taken because we are substracting last term and first term so it will not count one of that terms so +1 must have to be included)

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