There are no distinct whole number a, b and c such that a ÷ (b ÷ c) = (a ÷ b) ÷ c
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Step-by-step explanation:
Suppose a+b=c+d and a3+b3=c3+d3.
a+b=c+d
(a+b)3=(c+d)3
a3+b3+3ab(a+b)=c3+d3+3cd(c+d)
3ab(a+b)=3cd(c+d)
ab=cd
Let a+b=c+d=m and ab=cd=n
a and b are the roots of the quadratic equation
x2−mx+n=0
by Vieta's relations because a+b=m and ab=n. But c and d are also roots of the equation for similar reasons. But a quadratic equation can have at most two distinct roots.
Hence, a=c or a=d, so a,b,c,d are not distinct.
Mark a+b=x then b=x−a and d=x−c. Notice that x≠0. No we have:
a3+(x−a)3=c3+(x−c)3
and thus
−3x2a+3xa2=−3x2c+3xc2
so
xa−a2=xc−c2⟹x(a−c)=(a−c)(a+c)⟹x=a+c⟹a+c=a+b⟹c=b
A contradiction.
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