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- If roots are equal , then ∆ = 0
Given equation,
- (a²+b²)x² - 2(ac+bd)x + (c²+d²) = 0
Calculating the value of ∆
- ∆ = (2(ac+bd))² - 4(a²+b²)(c²+d²) = 0
- 4(ac)²+4(bd)²+8acbd -4(ac)² -4(ad)² -4(bc)² -4(bd)² = 0
- 8abcd - 4(ad)² -4(bc)² = 0
- -4(ad-bc)² = 0
- ad - bc = 0
- ad = bc
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