Question

There are six cards in a box, each bearing a number from 0 to 5. Find the probability of each of the following events, that a card drawn shows,
(1) a natural number.
(2) a number less than 1.
(3) a whole number.
(4) a number is greater than 5.

Answer 1

Answer:

(1)$= \frac{5}{6}$

(2)$= \frac{1}{6}$

(3)$= 1$

(4)$= 0$

Step-by-step explanation:

As per the question,

Number from 0 to 5 : 0, 1, 2, 3, 4, 5

Total numbers = 6

Probability is defined as the ration of favorable cases to the total cases.

(1) Natural numbers : 1, 2, 3, 4, 5

Total natural number from 0 to 5 = 5

∴ Probability of coming natural number $= \frac{5}{6}$

(2) Numbers less than 1 : 0

Total number less than 1 = 1

∴ Probability of coming a number less than 1 $= \frac{1}{6}$

(3) Whole numbers: 0, 1, 2, 3, 4, 5

Total whole number from 0 to 5 = 6

∴ Probability of coming whole number $= \frac{6}{6} = 1$

(4) Numbers greater than 5 : Nil

Total number greater than 5 = 0

∴ Probability of coming a number is greater than 5 $= \frac{0}{6} =0$

Answer 2

Answer:

(1)= /

(2)=1/

(3)=1

(4)= 0

Step-by-step explanation:

As per the question,

Number from 0 to 5 : 0, 1, 2, 3, 4, 5

Total numbers = 6