Math, asked by monark14, 1 year ago

there are some 50-paisa and
25-paisa coins in a bag. if total
number of coins is 25 and value of
coins is 8.50, find the number of
coins of each kind.
Answer the question in one variable.​


Anonymous: ___k off

Answers

Answered by TooFree
11

Answer:

50-paisa coins  = 9

25-paisa coins = 16

Step-by-step explanation:

Define x:

Let the number of 50-paisa coin be x

Since there is a total of 25 coins

Then the number of 25-paisa coins will be (25 - x)

Solve x:

The total value is 8.50

0.5x + 0.25(25 - x) = 8.50

0.5x + 6.25 - 0.25x = 8.5

0.25x = 2.25

x = 2.25 ÷ 0.25

x = 9

Find the coins:

50-paisa coins = x = 9

25-paisa coins = 25 - x = 25 - 9 = 16

Answer: There are 9 50-paisa coins and 16 25-paisa coins.


lakshita37: then his ans is wrong
monark14: then what is ans
TooFree: Yes, there are 2 types of coins - The 50-paisa coins and the 25-paisa coins.

50-paisa coins = 9
25-paisa coins = 16
Total coins = 9 + 16 = 25 (checked)
lakshita37: i am also not able to ans isnt there any other detail in the question
lakshita37: but u wrote since there are total of 25 coins
TooFree: Yes ... it is given that there are 25 coins in total
TooFree: So if we assumed that there are x number of coins that are 50-paisa, and there is a total of 25 coins, then (25 -x ) coins must be the 25-paisa coins.
monark14: no there is no other details
lakshita37: oh ya i didnt read the question properly silly of me
monark14: ok
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