Question

There are some chocolates in a jar. One child eats 1/4 of all the chocolates. A second child eats 1/3 of the remaining chocolates. If the remaining chocolates are distributed among five other children. What fraction of the original number of chocolates did each of the five children receive?
Explaination and steps
Please answer

Answer 1

Answer:

Step-by-step explanation:

Let x = Full box of chocolates.

x - 1/2x (Ana) - 1/5x (Pedro) = 12 (left in box)

Convert 1/2 and 1/5 to same denominator: 5/10 and 2/10

x - 5/10x - 2/10x = 12

x - 7/10x = 12

3/10x (number left) = 12

3x = 120

x = 40

So, the box when full had 40 chocolates in it.  1 ate 1/2 box = 20, andother  ate 1/5 box = 8, leaving 12 in the box.

Answer 2

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Answer:

Step-by-step explanation:

Let x = Full box of chocolates.

x - 1/2x (Ana) - 1/5x (Pedro) = 12 (left in box)

Convert 1/2 and 1/5 to same denominator: 5/10 and 2/10

x - 5/10x - 2/10x = 12

x - 7/10x = 12

3/10x (number left) = 12

3x = 120

x = 40

So, the box when full had 40 chocolates in it.  1 ate 1/2 box = 20, andother  ate 1/5 box = 8, leaving 12 in the box.