Question

There are three bottles of mixture of syrup and water of ratios 2 : 3, 3 : 4 and 7 : 5. 10 litres of the first and 21 litres of the second bottles are taken. How much quantity from third bottle is to be taken so that final mixture from three bottles will be of ratios

Answer 1

First bottle has 10 liters and ratio of syrup and water is 2:3

So, Amount of Syrup =10×2/5

=4 litres

Amount of Water =10×3/5

=6litres

2 bottles has 21 liters so ratio 3:4

Amount of Water =21×4/7

=12 liters

3 bottles has x liters and ratio of ayrup and water is 7:5

So, Amount of syrup =7x/12 litres

Amoumt of water = 5x/ 12 liters

Mixtures of ratio is 1:1

Means , total amount of syrup= total amount os water

= 4+9+7x/12 = 6+12+5x/12

= 7x/12 -5x/12 = 18-13 =5

= x/6 = 5

x= 30

Hence , 30 liters of quantity in 3 bottle