Question

There are three boxes. Box I contains 10 light bulbs of which 4 are
defective. Box II contains 6 light bulbs of which 1 is defective and box III
contains 8 light bulbs of which 3 are defective. A box is chosen and a bulb
is drawn. Find the probability that the bulb is defective.​

Answer 1

Answer:

p(e) = no. of outcome in favour/ total no. of outcome

= 4+1+3/24

=8/24 = 1/3 is the probability.