Question

There are three boxes on the top of a ramp. Box A has a mass of 3kg, and Box B has a mass of 2kg, and Box C has a mass of 5kg. When pushed, all three boxes moved with the same acceleration. Arrange the boxes in order of decreasing net force.​

Answer 1

Answer:

first keep the 3kg box then keep the 2kg box next to it without any gap and then keep the 5kg box at the other side.

Step-by-step explanation:

3+2 is 5 so if we keep 5 at both sides the weight will get balanced and the net force will decrease.

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Answer 2

Given,

Mass of box A $\[ = 3kg\]$

Mass of box B $\[ = 2kg\]$

Mass of box C $\[ = 5kg\]$

Solution,

It is given that all three boxes moved with same acceleration.

$\[net\,force = mass \times acceleration\]$

Consider the acceleration is $\[a.\]$

Net force on Box A,

$\[\begin{array}{l} = 3 \times a\\ = 3a\end{array}\]$

Net force on Box B,

$\[\begin{array}{l} = 2 \times a\\ = 2a\end{array}\]$

Net force on Box C,

$\[\begin{array}{l} = 5 \times a\\ = 5a\end{array}\]$

Arrange boxes in order of decreasing net force.

$\[\begin{array}{l} = 5a > 3a > 2a\\ = BoxC > BoxA > BoxB\end{array}\]$

Hence the decreasing order box according to net force is $\[BoxC > BoxA > BoxB\]$.