There are three boys more than the number of girls IN A CHESS CLUB.Member of the chess club is to be chosen at random to participate in a tournament. Each member is equally likely to be used.If the probability that a girl is chosen is 2/7 then, find how many girls and boys are there in the club.
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Let the number of girls be x and number of boys be x+3.
P(a girl is chosen)=2/7
2/7=No. of favourable outcomes/total no. of possible outcomes
2/7=x/x+x+3
2/7=x/2x+3
4x+6=7x. [Cross multiplication]
3x=6
x=2
Total no. of girls=2
& Total no. of boys=x+3=2+3=5
P(a girl is chosen)=2/7
2/7=No. of favourable outcomes/total no. of possible outcomes
2/7=x/x+x+3
2/7=x/2x+3
4x+6=7x. [Cross multiplication]
3x=6
x=2
Total no. of girls=2
& Total no. of boys=x+3=2+3=5
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