Math, asked by anubhaviaankhen5787, 1 year ago

There are three cities A, B and C, not on the same straight road.
Two buses P and Q start simultaneously from A and B respectively
towards C. By the time Q reaches C, P is exactly halfway to C.
Immediately after Q reaches C, it starts travelling towards A and it
crosses P at a point 165 km from A. The ratio of the speeds of P and
Q is 3 : 5. Assume that the roads joining A to C, B to C and B to A
are all straight roads. If B is twice as far as from A as it is from C
and P would take to cover the distance from A to B, how much
time would Q take to cover the distance from C to A?
(1)2 2/5 hours
(2) 3 hours
(3) 3 3/5 hours
(4) 4 hours

Answers

Answered by marmik1945
0
The time it would take is 3 hours .
Answered by amitnrw
2

Answer:

3 3/5 Hrs

Option 3 is right answer

Step-by-step explanation:

There are three cities A, B and C, not on the same straight road.

Two buses P and Q start simultaneously from A and B respectively

towards C. By the time Q reaches C, P is exactly halfway to C.

Immediately after Q reaches C, it starts travelling towards A and it  

crosses P at a point 165 km from A. The ratio of the speeds of P and

Q is 3 : 5. Assume that the roads joining A to C, B to C and B to A

are all straight roads. If B is twice as far as from A as it is from C

and P would take to cover the distance from A to B, how much

time would Q take to cover the distance from C to A?

(1)2 2/5 hours

(2) 3 hours

(3) 3 3/5 hours

(4) 4 hours

missing information

and P would take to cover the distance from A to B -  its 10 Hrs

Let say Speed of Bus P = 3x  kmHr

Speed of Bus Q = 5x  km/Hr

Let say in time t1 hr  Q reaches from B to C

5xt1 = BC    ( distance = Speed * Time)

3xt1 = AC/2  ( Q bus reaches half of AC in same time )

5xt1/3xt1 = BC/(AC/2)

=> 5/3 = 2BC/AC

=> 5AC = 6BC

let say after t2 he time Q & B crosses each other at AC (165 km from A)

5xt2 = AC - 165

3xt2 = 165 - AC/2

5xt2/3xt2  = (AC - 165)/(165 - AC/2)

=> 5/3 = (AC -165)/{(330 - AC)/2}

=> 5 (330-AC) = 6 (AC - 165)

=> 1650 - 5AC = 6AC - 990

=> 2640 = 11AC

=> AC = 240 km

5AC = 6 BC

=> BC = 5 * 240 / 6 = 200

BC = 200 km

BA = 2BC given

BA = 2 * 200 = 400

BA = 400 km

P take 10 hours from A t o B

P speed = 400 / 10

P speed = 40 km/Hr

P speed = 3x

3x = 40

x = 40/3

Q speed = 5x

Q speed = 5 * 40/3

Q speed = 200/3 km/Hr

Distance from C to A = 240 km

Time taken = 240/(200/3)

= 720/200

= 18/5 hrs

= 3 3/5 Hrs

Option 3 is right answer

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