Question

There are three consecutive integers. The sum of the first two is 51 more than the third. Find the integers. I need help!

Answer 1

let the 1st integer is x
2nd is x+ 1
3rd is x+2

so from question

x+x+1= x+2+51
solve it

x = 52

so the integer is 52,53,54


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Answer 2

Answer:

Step-by-step explanation:

Let the required consecutive integer be x,x+1 and x+2.

A/Q x+(x+1)=(x+2)+51

2x+1=x+53

x=52

Therefore, 1st integer = 52

2nd integer = 53

3rd integer = 54