two numbers have these properties they are greater then 6 they have a hcf of 6 and a lcm of 60
Answers
Given : HCF=6 and LCM=60
Both numbers are greater than 6.
Find : Both the numbers
- For two numbers a and b: a×b=LCM×HCF.
- Here a×b=60×6
=360.
As now HCF of both the numbers is 6,so both should be a multiple of 6
Hence the numbers can either be (6,60) or (12,30), but as both the numbers are greater than 6 so the answer is (12,30).
12 and 30 are the numbers greater then 6 having HCF of 6 and LCM of 60
Given : Two numbers have these properties they are greater then 6 they have a HCF of 6 and a LCM of 60
To Find : Numbers
Solution:
Two numbers having HCF 6 can be
6a , 6b where a, b are co prime a , b > 1 as numbers are greater then 6
HCF * LCM = Product of Numbers
=> 6 * 60 = 6a * 6b
=> 10 = ab
ab = 10
10 = 1 * 10 = 2 * 5
a , b > 1
Hence a nd b can be 2 or 5
numbers are 6 * 2 , 6 * 5
= 12 and 30
12 and 30 are the numbers greater then 6 having HCF of 6 and LCM of 60
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