Question

There are three consecutive numbers. The sum of the first two is 20 more than the third. What are the numbers?

Answer 1

Answer:

the numbers are 21, 22 and 23

Step-by-step explanation:

let the numbers be x , x+1 and x+2

x+x+1=x+2+20

2x+1=x+22

x=21

Answer 2

Given,

There are three consecutive numbers.

The sum of the first two is 20 more than the third.

Solution,

Consider three consecutive numbers are $\[x - 1,x,x + 1\]$.

$\[\begin{array}{l}x - 1 + x + 20 = x + 1\\ \Rightarrow 2x + 19 = x + 1\\ \Rightarrow x = - 18\end{array}\]$

Calculate the numbers,

First number,

$\[\begin{array}{l} = x - 1\\ = - 18 - 1\\ = - 19\end{array}\]$

Second number,

$\[\begin{array}{l} = x\\ = - 18\end{array}\]$

Third number,

$\[\begin{array}{l} = x + 1\\ = - 18 + 1\\ = - 17\end{array}\]$

Hence the consecutive numbers are $\[ - 19, - 18, - 17\]$