Question

there are three heaps of wheat weighing 510 kg 408 kg and 1054 kg find the maximum capacity of bags so that the wheatof each heap can be packed in exact number of the bags​

Answer 1

10,8,21bags are required

Answer 2

Answer:

17

Step-by-step explanation:

We are given that there are three heaps of wheat weighing 510 kg 408 kg and 1054 kg

We are supposed to find the maximum capacity of bags so that the wheat of each heap can be packed in exact number of the bags​.

Find HCF

5  |  510         2 | 408     2  | 1054

2  |  102         2 | 204     17 |  527

3  |  51           2 |  102     31  |  31

17 |  17           3 |   51            | 1

   |  1             17 |  17

                         | 1

$510 = 5 \times 2 \times 3 \times 17$

$408 = 2 \times 2 \times 2 \times  3 \times 17$

$1054 = 2 \times  17 \times 31$

HCF = 17

Hence the maximum capacity of bags so that the wheatof each heap can be packed in exact number of the bags​ is 17