Question

there are three numbers a,b and c,b is 2 times a,c is 0.2 times b.the sum of thier cube if 9.064.find the value of b?

Answer 1

b=2

a^3+b^3+c^3=9.064 (given)

b=2a (given)

c= 0.2b (given)

a^3+ (2a)^3 + (0.2×2a)^3= 9.064

a^3+8a^3+0.064a^3=9.064

9.064a^3= 9.064

a^3= 1

a=1

b=2a

b=2×1=2