Question

There are three red marbles, four blue marbles, and five green marbles in a bag. What is the probability of choosing a red marble, NOT replacing it, and then choosing a green marble.

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Answer 1

Answer: $\frac{5}{44}$

Step-by-step explanation:

We have 3 red marbles , 4 blue marbles , and 5 green marbles .  

First the probability of choosing a red marble is (no. of red marbles)/(total no. of marbles) = $\frac{3}{12}$ = $\frac{1}{4}$

Then we would be having 11 marbles left in the bag . (since we already chose 1 red marble)

So the probability of choosing a green marble next time = $\frac{5}{11}$

So the total probability of choosing a red marble without replacing it and then choosing a green marble = $\frac{1}{4} * \frac{5}{11}$ = $\frac{5}{44}$

Hope this helps you .

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Answer 2

Answer:

Probability of choosing a red marble is 1/4

Probability of choosing a green marble without replacing the red marble is 1/6