There are three resistors joined in series in a system having resistance equal to 10 Ω, 20 Ω and 30 Ω respectively. find the total resistance and current through the circuit.
Answers
Answered by
4
Answer:
60 Ω
Explanation:
In series combination the total resistance is calculated as:-
R = R1+ R2.......Rn
where n is constant
Resistance = 10Ω + 20Ω + 30Ω
= 60Ω
Answered by
7
Answer:
Total resistance = 60 Ω
Current flowing = 3.66 amperes
Explanation:
Given:
Resistance of resistor 1 = 10 Ω
Resistance of resistor 2= 20 Ω
Resistance of resistor 3 = 30 Ω
They are connected in series
To find :
- Total resistance
- Current through the circuit
When any two resistors are connected in series Req = R1+R2]
In the above case,
Total resistance = 10Ω+20Ω+30Ω
Total resistance = 60Ω
The total resistance across the circuit is equal to 60Ω
As potential difference is not given, i am assuming it as 220V
V=IR
220=I×60
I = 220/60
I = 3.666 Amperes
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