Physics, asked by shivangi2904, 10 months ago

There are three resistors joined in series in a system having resistance equal to 10 Ω, 20 Ω and 30 Ω respectively. find the total resistance and current through the circuit.

Answers

Answered by sagnikmajhi98
4

Answer:

60 Ω

Explanation:

In series combination the total resistance is calculated as:-

R = R1+ R2.......Rn

where n is constant

Resistance = 10Ω + 20Ω + 30Ω

= 60Ω

Answered by Anonymous
7

Answer:

Total resistance = 60 Ω

Current flowing = 3.66 amperes

Explanation:

Given:

Resistance of resistor 1 = 10 Ω

Resistance of resistor 2= 20 Ω

Resistance of resistor 3 = 30 Ω

They are connected in series

To find :

  • Total resistance
  • Current through the circuit

When any two resistors are connected in series Req = R1+R2]

In the above case,

Total resistance = 10Ω+20Ω+30Ω

Total resistance = 60Ω

The total resistance across the circuit is equal to 60Ω

As potential difference is not given, i am assuming it as 220V

V=IR

220=I×60

I = 220/60

I = 3.666 Amperes

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