There are three runners Ram, Gautam, and Shyam with their respective speeds of 10kmph, 20kmph and 30kmph they are initially at P and they have to run between the two points P and Q which are 10 km apart from each other. They start their race at 6 am and end at 6 pm on the same day. If they run between P and Q without any break, then how many times they will be together either at P or Q during the given time period?
Answers
Answer:
They will meet at P 8 AM , 10 AM , 12 PM , 2 PM , 4PM , 6PM
They Will meet 6 times
Step-by-step explanation:
There are three runners Ram, Gautam, and Shyam with their respective speeds of 10kmph, 20kmph and 30kmph they are initially at P
Ram speed = 10 km/hr
P to Q distance = 10 km
P to Q time = 10/10 = 1 hr
Ram will Reach point Q first after 1 hr
Then Every 2 hrs ( as he has to cover 20 km then Q to P & P to Q)
Ram at Q 7 AM , 9 AM , 11 AM , 1 PM , 3PM , 5PM
Ram at P 8 AM , 10 AM , 12 PM , 2 PM , 4PM , 6PM
Gautam speed = 20 km/hr
Gautam will Reach point Q first after 1/2 hr
then after 1 Hr Each
Gautam at Q 7:30AM , 8:30AM ..............................5:30PM
so They will never meet at Q
Gautam at P will be Every hr
7 AM , 8 AM , 9 AM ......... 5PM , 6PM
for Shayam we will not check Q as Ram & Gautam will never meet at Q
Shayam speed = 30 km/hr
Shayam will be at P every 2/3 hr
Shayam at P 6:40AM , 7 :20AM , 8 :00AM ,,,,,,
=> Every Two Hrs Ram, Gautam, and Shyam will be at P
They will meet at P 8 AM , 10 AM , 12 PM , 2 PM , 4PM , 6PM
They Will meet 6 times