there are three types of item in a box: pencils scales and erasers. if the number of pencils is double the number of erasers and the number of scales is the square of the number of pencils, find each item if the total number of item is 45.
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Let the total no. of erasers be y
Therefore, total no. of pencils= 2y
Total no. of scales= (2y)^2= 4y^2
Now,
As per ques.
4y^2+2y+y=45
4y^2+3y=45
4y^2+3y-45=0
4y^2-12y+15y-45=0
4y(y-3)+15(y-3)=0
(4y+15)(y-3)=0
Therefore,
Total no. of erasers= 3
Pencils= 2×3=6
Scales= 4×9=36
Hope this may help u
Therefore, total no. of pencils= 2y
Total no. of scales= (2y)^2= 4y^2
Now,
As per ques.
4y^2+2y+y=45
4y^2+3y=45
4y^2+3y-45=0
4y^2-12y+15y-45=0
4y(y-3)+15(y-3)=0
(4y+15)(y-3)=0
Therefore,
Total no. of erasers= 3
Pencils= 2×3=6
Scales= 4×9=36
Hope this may help u
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