There are tokens numbered from 1 to 30 in abox .one token is taken out of it at random.what is the probability the token taken out is (an even number) (a multiple of 5)a prime number
shivamone:
answer for A is 14/30 b is 6/30 and prime is c is 1/30
Answers
Answered by
3
HeYA!!
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Probability of an Event P ( E ) = No. Of Favourable Outcomes / Total Number of Outcomes
Here , Total possible Outcomes = 30
A. ] P ( Even Number ). = 15 / 30
= 1 / 2
B]. P ( A Multiple of five ) = 6 / 30
= 1 / 5
C. ] P ( A prime Number )
= 10 / 30
= 1/3
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--------
Probability of an Event P ( E ) = No. Of Favourable Outcomes / Total Number of Outcomes
Here , Total possible Outcomes = 30
A. ] P ( Even Number ). = 15 / 30
= 1 / 2
B]. P ( A Multiple of five ) = 6 / 30
= 1 / 5
C. ] P ( A prime Number )
= 10 / 30
= 1/3
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Answered by
1
the probability of even no comes out of random will be
1/2.
the probability of multiple of 5 is 1/5
the probability of prime no. is 1/3.
Hope it helps uu
1/2.
the probability of multiple of 5 is 1/5
the probability of prime no. is 1/3.
Hope it helps uu
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