Question

There are two alloys of gold and silver . In the first alloy, there is twice as much gold as silver , and in the second ally there is 5 times less gold than silver. How many times more must we take of the second alloy than the first in order to obtain a new alloy in which there would be twice as much silver as gold ?

Answer 1

We can do this question in a similar fashion to the other one.  

There are 3 kg of copper and 1 kg of silver in every 4 kg of the first alloy.  

There is 1 kg of copper and 4 kg of silver in every 5 kg of the second alloy.  

So to get equal amounts of the two alloys, we will multiply the first set of numbers by 5 and the second set of numbers by 4, as follows:  

There are 15 kg of copper and 5 kg of silver in every 20 kg of the first alloy.  

There are 4 kg of copper and 16 kg of silver in every 20 kg of the second alloy.  

Let the number of times more of the required of the first alloy = x.  

Then the third alloy contains (15x + 4) kg of copper and (5x + 16) kg of silver. We require 15x + 4 = 2(5x + 16)  

15x + 4 = 10x + 32  

5x = 28  

Thus we require 5.6 times as much of the first alloy as of the second alloy.

Answer 2

Answer:

2 times

Explanation:

according to question the ratio of gold and silver in alloy 1 and 2 is :

G S

Alloy I ; 2 : 1

Alloy II ; 1 : 5

Alloy I & II combine ; 1 : 2

By making these ratio equal and applying Allegation we can get our answer

As

G S

I 2 : 1 * 2. = 4 : 2

II. 1 : 5 * 1 = 1 : 5

I & II 1 : 2 * 2. = 2 : 4

we can take any side gold and silver ans will remain same

I have taken silver side to solve this question

I. II

2. 5

4

1. : 2

HENCE : WE NEED 2 TIMES OF ALLOY I