Question

there are two concecutive numbers such that one-fifth of the greater exceeds one-seventh of the lesser by 3. Find the numbers

Answer 1

let the numbers be n and n+1
ATQ:
(1/5)(n+1)-(1/7)n=3
7(n+1)-5n=3*5*7
2n+7=105
2n=98
n=49
ur numbers are 49 and 49+1.
done.