There are two concentric circles with centre o. Prt and pqs are tangents to the inner circle from a ppint p lying on the outer circle. If pr=5cm, find the length of ps
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Given:
PQS and PRT are tangents to inner circle.
PR = 5 cm
To find:
PS=?
As we know,
PR = PQ = 5cm ( tangents from common point)
And also,
PQ = QS = 5cm (OQ is the radius, so it bisects PS)
Therefore,
PS = PQ + QS = 5+5= 10 cm
PS=10 cm
HOPE IT HELPS!!
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