Question

there are two cones having same volume of radius 6 cm and 8 cm then the ratio of their Heights are respectively is

Answer 1

Answer: ur answer is 16:9

Step-by-step explanation:

v1= 1/3 * 22/7 * 6^2 *h1

v2= 1/3 * 22/7 * 8^2 * h2

a/q, 1/3 * 22/7 * 6^2 *h1 =  1/3 * 22/7 * 8^2 * h2

      36 * h1 = 64 * h2

      h1 : h2 = 64 : 36

      h1 : h2 = 16 : 9

Answer 2

⭐Hey there!!

$volume = \frac{1}{3} \pi \ r {}^{2} h$

so r1 =6 cm ,

=> r2 = 8cm

#let the height of cones is h1 and h2

But given that : V1 = V2

=> 1/3 π(r1)²h1 = 1/3 π(r2)²h2

=> (6)²h1 = (8)²h2

=> h1/h2 = 64/36 = 16/9

so the ratio of their heights are => 16 : 9

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⭐Hope it will help you