Question

There are two container of equal capacity . The ratio of milk to water in 1st can 5:3 and in 2nd can is 4:3. If they are mixed up, what is the new ratio?
A) 45:67
B) 55:68
C) 67:45
D) 37:45
E) None​

Answer 1

Answer:

Let the containers of equal capacity be holding mixture of 56 (LCM of 8 and 7)

First Container –

• Container holding Milk :

⇒ Milk = Ratio/Total Ratio × Capacity

⇒ Milk = 5/(5 + 3) × 56

⇒ Milk = 5/8 × 56

⇒ Milk = 5 × 7

⇒ Milk = 35

• Container holding Water :

⇒ Water = Total - Milk

⇒ Water = 56 - 35

⇒ Water = 21

Second Container –

• Container holding Milk :

⇒ Milk = Ratio/Total Ratio × Capacity

⇒ Milk = 4/(4 + 3) × 56

⇒ Milk = 4/7 × 56

⇒ Milk = 4 × 8

⇒ Milk = 32

• Container holding Water :

⇒ Water = Total - Milk

⇒ Water = 56 - 32

⇒ Water = 24

⠀⠀⠀⠀⠀───────────────

Both Containers are mixed, now we have to find Ratio of Milk and Water in new mixture.

• Ratio in New Mixture :

⇢ Milk : Water = (1st + 2nd) : (1st + 2nd)

⇢ Milk : Water = (35 + 32) : (21 + 24)

⇢ Milk : Water = 67 : 45

∴ Hence, correct option is C) 67 : 45.