Math, asked by athipathy97, 10 months ago


There are two containers A and B filled with mentha oil with
different prices and their volumes are 140 litres and 60 litres
respectively. Equal quantities are drawn from both A and B in
such a manner that the oil drawn from A is poured into B and
the oil drawn from B is poured into A. The price per litre
becomes equal in both A and B. How much oil is drawn from
each of A and B :
(a) 40 litre
(b) 21 litre
(C) 42 litre
(d) can't be determined​

Answers

Answered by s7388
13

Let price of container A = x / Litre

Let price of container B = y/ Litre

Let L litre is drawn from A and poured into B and vice versa.

Total price of container A = (140-L)x + added quantity's price from B (Ly)

i.e A = (140-L)x + Ly

hence, Price of container B = (60-L)y + Lx

now, A=B and their volume will be equal also.

so, { (140-L)x + Ly }/140 = { (60-L)y + Lx } /60

3(140x - Lx + Ly) = 7(60y - Ly +Lx)

after solving...

42(x-y) = L(x-y)

L = 42 litre was drawn from each container.

Answered by mauryasmita12
0

Answer:

is there any other way for this?

Step-by-step explanation:

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