Question

There are two containers on a table. A and

b. A is half full of wine, while b, which is twice a's size, is one-quarter full of wine. Both containers are filled with water and the contents are poured into a third container

c. What portion of container c's mixture is wine?

Answer 1

Answer:

I did not remember your question..

Answer 2

Answer:

33.33

Step-by-step explanation:

Let d size of container A is "x"

then B's size ll be "2x"

A is half full of wine -- >x/2

So remaining "x/2" of A contains water

B is quarter full of win --> 2x/4 --> x/2

So remaining ==> 2x - x/2 = 3x/2

3x/2 of B contains water

Totally C has A's content + B's Content = x + 2x =3x

Wine portion in C = x/2 of "A" + x/2 of "B"

==> x portion of wine

Water portion in C = x/2 of "A" + 3x/2 of "B"

==> 4x/2 ==> 2x portion of water

So portion of wine in C is

x/3x =1/3 portion of wine

if v expressed in %

1/3 * 100 = 33.33%

Ans : 33.33% of wine