Question

There are two n u mbers with the difference of 3 between them and the difference of their squares is 51. can you find the numbers?

Answer 1

Let the first number be X So when X> second number then second number is X-3 So when second number>X  then second number is X+3 ATQ WHEN X> second number (X)^2-(X-3)^2=51 X^2-X^2-9+6X=51 6X-9=51 6X=60 X=10 SO SECOND NUMBER=10-3=7 WHEN X<SECOND NUMBER (X+3)^2-X^2=51 X^2+9+6X-X^2=51 6X+9=51 6X=42 X=7  SO SECOND NUMBER IS 7+3=10 SO THE NUMBERS ARE 10,7 OR 7,10