Question

There are two numbers. Five times the first and four times the second are equal. Find the ratio
of the sum of the squares of the two numbers and their product.

Answer 1

Answer:

Given : two numbers are such that the sum of twice the first and thrice the second is 92, and four times the first exceeds seven times the second by 2.

To find : the two numbers

Let x and y be the two numbers required.

According to the question :

⇒2x+3y=92 ........(1)

⇒4x−7y=2 ........(2)

multiply the first equation by 2 , and subtract eqn (1) from eqn (2)

4x+6y=184

−(4x−7y=2) , we get

⇒13y=182

⇒y=

13

182

=14

Put y=14 in (1)

2x+3y=92

⇒2x+3×14=92

⇒2x=92−42=50

∴x=

2

50

=25

∴x=25 and y=14

Answer 2

hi there!

I hope my answer helps you with your question and the answer is (4 ration 5) 4:5  

plz reply