Question

There are two numbers in the ratio 8:9. if the smaller of the two numbers is
increased by 12 and the larger number is reduced by 19 thee the ratio of the two
numbers is 5:9.


Find the larger number.

Answer 1

X1 : X2 = 8:9,

(X1 +12) * 9 = (X2 - 19) * 5,

9x1 + 108 = 5x2 - 95,

9x1 - 5x2 = -203,

9x1 = 8x2,3x2 = -203,

x2 = -203/3,x1 = 8x2/9,

Answer 2

Let the numbers be 8x and 9x
then 8 x + 12 ÷ 9 x- 19 is equal to 5 by 9
9(8x+12)=5(9x-19)
72x+108=45x-95
72x-45x=-95-108
27x=-203
X=-203/27
Friend now u find the larger no.
Hope it helped u friend
Mark as brainliest plzzzzzzzzz please