Question

There are two numbers such that 20% of the first
number is equal to the cube of the second number.
The second number is 16/13 % of 650. What is the
sum of the two numbers?
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Answer 1

Answer:

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Answer 2

Answer:

let the numbers be x and y.

ATQ

$x \times \frac{20}{100} = {y}^{3}$

And

$y = \frac{16}{13} \times 650 \times \frac{1}{100} \\ y = 8$

So,

$x = {y}^{3} \times \frac{100}{20} \\ x = 8 \times 8 \times 8 \times \frac{100}{20} \\ x = 2560$

So, sum = 2560+8

=2568