Question

there are two numbers such that sum of the numbers is 50 and the difference is 14 find the difference of their cubes​

Answer 1

Step-by-step explanation:

let one number = x and second number is y

given:x+y=50............(1)

x-y=14...............(2)

x=50-y (from 1)

substituting the value of x in (2)

50-y-y=14

50-2y=14

-2y=14-50

-2y=-36

y=18

putting value of y in (1)

x+14=50

x=36

now we have to find the difference of their cubes

x^3-y^3=36^3-14^3

46656-2744

43912

Answer 2

Answer:

⇒ x - y = 26,936

Step-by-step explanation:

Let one number be 'x' & second number be 'y'

Now , Given that ;

=> x + y = 50 (i)

And,

=> x - y = 14 (ii)

Then ,

⇒x = 50 - y _________from (i)

Substituting the value of x in (ii), we get ;

⇒50 - y - y = 14

⇒50 - 2y = 14

⇒ - 2y = 14 - 50

⇒ - 2y = -36

⇒ y = 36/2 = 18

Putting value of y in (i), we get ;

⇒x + y = 50

⇒x + 18 = 50

⇒x = 50 - 18

⇒x = 32

Now , we have ;

x = 32 & y = 18.

Now , finding cubes ;

⇒x = 32 × 32 × 32 = 32,768

⇒y = 18 × 18 × 18 = 5,832

Now , find the difference between x & y ;

⇒x - y = 32,768 - 5,832

∴ x - y = 26,936