There are two numbers such that the sum of twice the first number and thrice the second number is 300 and the sum of thrice the first number and twice the second number is 265. what is the larger number?
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let the no. S be a and b
given,
2a+3b=300
3a+2b=265
solve multiplyfirst by 3 and second by 2
6a+9b=900
6a+4b=530
sub....
b=74
a=39
given,
2a+3b=300
3a+2b=265
solve multiplyfirst by 3 and second by 2
6a+9b=900
6a+4b=530
sub....
b=74
a=39
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