there are two or more birds in 40%cages out of tge cages with one bird there was one male bird only in 25%cages .find the percentage of those cages in which there live only one female bird and no male bird out of all the cages.
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Answer:
45 %
Step-by-step explanation:
Let say Total Cages = 100T
two or more birds in 40%cages = (40/100)100T = 40T
in 40T cages two or more birds
=> Cages in which only one Bird = 100T - 40T = 60T
male bird only in 25%cages of 60T
=> Male Bird = (25/100) 60T = 15T
Female Bird only in Cages = 60T - 15T = 45T
percentage of those cages in which there live only one female bird
= (45T/100T) * 100
= 45 %
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