Question

There are two pairs of prime consecutive numbers. The first number in the second pair is 4 less than 15 times the first number of the first pair. Sum of the first numbers in the two pairs is 76. Find the numbers in both pairs.​

Answer 1

Answer:

Let the numbers be a,b and c,d

So c=15a-4

Also, a+c=76

15a-4+a=76

16a=80

a=5

then c=15*5-4=75-4=71

the best prime number to 5 is 7 so, b=7

And the next prime number to 71 is 73, so d=73